Question by john: A company manufactures computer elements. Assume that the probability of any distinct element becoming defe?
A organization manufactures laptop elements. Assume that the probability of any certain component becoming defective is .18. Discover the probability that the first defect is discovered in the sixth component tested. (Round your answer to 4 decimal areas.)
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Answer by Arthur
In order for the 1st defect to be found as the sixth component tested, the 1st 5 must succeed and the sixth need to fail (in that order). Let A(i) = Chip i succeeds and B(i) = Chip i fails. p(A(i)) = .82 and p(B(i)) = .18. Thus p(A(1) & A(two) & A(three) & A(4) & A(five) & B(six) ) = .82^5 * .18^1 = .0667 = 6.67%
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